mfz

It works the same because the value of the last expression in the for loop is not used for anything. It’s the side effect of that statement that counts. Eg, the value of i is checked the next time the for loop is executed by the condition check. Try replacing i in the condition check instead with i++ or ++i and you would see different results.

Something like: for (int i = 0; ++i < 10;) { ... }

Well, not all languages allow for fun programming :)

In C you can group expressions within ( and ) separated with ,. Expressions are evaluated in order and the last expression in the group is the returned value of the group.

If you’re hell bend on achieving the goodness of i++ equivalent you could wrap it up like this:
(i-=-1,i-1)

We’re talking C here of course.

Isn’t the evaluated value different from the expression? i++ returns the value of i before increasing. i-=-1 would return the value after it has been increased. Wouldn’t it be more correct to make it equal to ++i

Yes, yes, and someone else’s problem will be your problem after the job hop! :)